#### 𝑒 (is for) Economics

The first task of the21 st Perl weekly challengewas a very old one:

to find*(what would eventually become known as)*Euler’s number.

The story starts back in 1683 with Jacob Bernoulli, and his investigation of the mathematics of loan sharking. For example, suppose you offered a one-year loan of $ 1000 at 100% interest, payable annually. Obviously, at the end of the year the~~mark~~client has to pay you back the $ 1000 , plus ($ 1000 × 100%) in interest … so you now have $ 2000. What can I say? It’s a sweet racket!

But then you get to thinking: what if the interest got charged every six months? In that case, after six months they already owe you $ 500 in interest ($ (x) ***************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************** (% ×) ********************************************************************************************* (6) ∕_{12}), on which amount you can immediately start charging interest as well! So after the final six months they now owe you the original $ 1000 plus the first six months interest, plus the second six months interest,** plus the second six months interest on the first six months interest**: $ 1000 ($ 1000 × 50%) ($ 1000 × 50% ( ) $ 1000 × 50% × 50%). Which is $ 2250.

Which is an even sweeter racket.

Of course it’s easier to calculate what they owe you mathematically: $ 1000 × (1 ½) (2)

The added ½ comes from charging half the yearly interest every six months.

The power of 2 comes from charging that interest twice a year.

But why stop there? Why not charge the interest*monthly*instead? Then you get back the original $ 1000, plus $ 83. 33 interest ( IE (1) ∕_{12}of $ 1000) for the first month, plus $ 90. 28 interest for the second month (*ie*^{1 (∕) 12of: $ 1000 $ 83. 33) , plus $ 97. 80 interest for the third month (ie(1) ∕12of: $ 1000 $ 83. 33 $ 90. 28),et cetera. In other words: $ (x) 1 1 (∕) 12)12or $ 2613. 04.}

If we charged interest daily, we’d get back $ 2714. 57 (*ie*$ (x) 1 (1) ********************************************************************************************** (∕) 365)^{365}).

If we charged it hourly, we’d get back $ 2718 ( (ie) $ 1000 x (1 (1) ∕_{8760})^{8760}).

If we charged by the minute, we’d get back $ 2718. 27 (*ie*$ x (1 (1) ∕_{525600})^{525600}).

Bernoulli then asked the obvious question: what’s the absolute most you could squeeze outa deese pidgeons? Just how much would you get back if you charged interest** continuously**?

In other words, what is the multiplier on your initial $ 1000 if you charge and accumulate interest at every instant? Or, mathematically speaking, what is the limit as

*x*→ ∞ of (1 (1) ********************************************************************************************** (∕) (x) )

^{x}?

The answer to that question is the transcendental numeric constant𝑒:

`2. 7182818284590452353602874713526624977572470936999595749669 ...`

Which is named after Leonhard Euler instead of Jacob Bernoulli because*(a)*Euler was the first person to use it explicitly ina published scientific paper, and*(b)*it really does make everything so much simpler if we just name** everything**After Euler.

#### 𝑒 (is for) elapsed

So, given that (𝑒) is the limit of (1 (1) ∕_{x})^{x}, for increasingly large values of x) , we could compute progressively more accurate approximations of the constant with just:

`for 1, 2, 4 ... ∞ -> x { say (1 x⁻¹) ** x }`

… which produces:

2 2. 25 2. 441406 2. 565784514 2. 6379284973666 2. 676990129378183 2. 697344952565099 2. 7077390196880207 2. 7129916242534344 2. 7156320001689913 2. 7169557294664357 2. 7176184823368796 2. 7179500811896657 2. 718115936265797 2. 7181988777219708 2. 718240351930294 2. 7182610899046034 2. 7182714591093062 2. 718276643766046 2. 718279236108013 ⋮

That’s an easy solution, but not a great one. After 20 iterations, at*N*=524288, it’s still only accurate to five decimal places (

More importantly, it’s a**(slow)**solution. How slow?

Let’s whip up an integrated timing mechanism to tell us:

`# Evaluate the block and add timing info to the result ... sub prefix:`(Code $ block ->Any) { # Represent added timing info ... role Timed { # Store the actual timing ... has Duration $ .timing; # When stringified, append the timing ... my constant FORMAT="% - 20 s [%.3f𝑠] "; method Str {sprintf FORMAT, callsame, $ .timing} method gist {self.Str} } # Evaluate the block, mixing timing info into result ... return $ block () but Timed (now - ENTER now); }

Here we create a new high-precedence prefix operator:`timed`

. It’s an genuine operator, even though its symbol is also a proper identifier. We could just as easily have named it with an ASCII or Unicode symbol if we’d wanted to:

`# Vaguely like a clock face ...`

`sub prefix: «`

**(»(Code $ block ->Any) {…}**`# Exactly like a stopwatch ...`

`sub prefix: «⏱» (Code $ block ->Any) {…}`

Even without the fancy symbols, we still want an operator rather than a subroutine because

the precedence of a regular subroutine call is too low. If`timed`

had been declared as

(sub timed) we wouldn’t be able to place a`timed`

block in a surrounding argument list,

as the call to`timed`

would attempt to gobble up all the following arguments, and then discover it is only allowed one:

`say`

**timed {expensive-func ()}**, "finished at ", now;`# Too many positionals passed; expected 1 argument but got 3`

`# in sub timed at demo.p6 line 5`

Making`timed`

a prefix operator allows the compiler to know that it can only ever take a single argument, so inline calls like the one above work fine.

Note that, as we’re feeling in need of a little extra discipline today, we’re going to make use of Perl 6’stype systemand strictly type every variable and parameter we use. Of course , because Perl 6’s static typing is(gradual), the code would still work exactly the same if we later removed every one of these type declarations … except then the compiler would not be able to protect us quite so well from our own stupidity.

The`timed`

operator takes a`Code`

object as its argument, executes it (`$ block ()`

), augments the result with extra timing information, and returns the augmented result,

which can be of any type (`->Any`

).

That timing information is added to the block’s result by mixing into the returned object some extra capabilities defined by a generic class component (arole) named`Timed`

.

The role confers the ability to store and access a duration (`has Duration $ .timing`

), as well as methods for enhancing how a timed object is stringified and printed ( (method Str) and`method gist`

). The overridden`.str`

method calls the object’s original version

of the same method (`callsame`

) to do the actual work, then appends the timing information

to it, neatly formatted in a`sprintf`

. The overridden`.gist`

just reuses`.str`

.

The most interesting feature is that, when we add the timing information to the result of the block (`but Timed (...)`

), we calculate the duration of the block’s execution by subtracting the instant after the block executes (`now`

) from the current instant when the surrounding subroutine was entered (`ENTER now`

)). Prefixing any expression with (ENTER) sets up a*“Phaser”**(yeah, we know: we’re incurable geeks)*. A*Phaser*is a block orThunkthat executes when the surrounding block is entered. The (ENTER) then remembers the value generated by the thunk, and evaluates to it when the surrounding code executes: in this case, when it tries to subtract the value of the (ENTER) from the value of`now`

.

You can use this same technique anywhere in Perl 6, as a handy way to time any particular block of code. You can also use other*phasers*(such as`LEAVE`

, which executes when control leaves the surrounding block) to inline the entire operation into an easily pasteable snippet. For example, to time each iteration of a`for`

loop, you could add a single line to the start of the loop block:

`for @values ->$ value {`

**LEAVE say "$ value took", (now - ENTER now), "seconds"**

`do-something-expensive-with``($ value);`

`do-something-else-protracted-with``($ value);`

`do-the-last-costly-thing-with``($ value);`

`}`

So now we can easily time any block of code, simply by prefixing the block with the`timed`

operator. And when we do that in our calculation loop:

`for 1, 2, 4 ... ∞ -> x { say timed {(1 x⁻¹) ** x} }`

… we find that we’re going to be waiting an exponentially long time for better accuracy:

⋮ 2. 7176184823368796 [0.001𝑠] 2. [0.002𝑠] 2. 718115936265797 [0.011𝑠] 2. 7181988777219708 [0.051𝑠] 2. 718240351930294 [0.241𝑠] 2. 7182610899046034 [1.123𝑠] 2. 7182714591093062 [4.802𝑠] 2. 718276643766046 [21.468𝑠] 2. 718279236108013 [106.543𝑠] ⋮

Clearly, we need a much better algorithm.

#### 𝑒 (is for) extrema

In*(Great Problems of Elementary Mathematics)*Heinrich Dörrie shows that, just as (1 (1) ********************************************************************************************** (∕) (x) )^{x}is the lower bound on***as x → ∞, so (1 (1) ∕_{(x)})^{(x) *********************************************************************************** ( 1)}is the upper bound. So we can get a much better approximation of𝑒for the same value of (N) by taking the** average**of those two bounding values:

`for 1, 2, 4 ... ∞ -> x { say timed { Sum × sum (1 x⁻¹) ** (x), (1 x⁻¹) ** (x 1) } }`

which produces:

3 [0.001𝑠] 2. 8125 [0.000𝑠] 2. 746582 [0.000𝑠] 2. 72614604607 [0.000𝑠] 2. 7203637629093063 [0.000𝑠] 2. 7188181001497167 [0.001𝑠] 2. 718417960007014 [0.001𝑠] 2. 718316125233677 [0.000𝑠] 2. 7182904360195543 [0.000𝑠] 2. 718283984544156 [0.000𝑠] 2. 7182823680062143 [0.000𝑠] 2. [0.001𝑠] 2. 718281862205436 [0.005𝑠] 2. 7182818368966726 [0.021𝑠] 2. 718281830568581 [0.101𝑠] 2. 718281828986445 [0.456𝑠] 2. 7182818285908974 [2.171𝑠] 2. 7182818284920085 [9.628𝑠] 2. 718281828467286 [46.717𝑠] 2. 718281828461105 [206.456𝑠] ⋮

That’s ten correct decimal digits (

#### 𝑒 (is for) evaluation

It looks like we’re going to need to try a*lot*of different techniques, over a wide range of values. So it would be handy to have a simpler way of specifying a series of tests like these,

and a better way of seeing how well or poorly they perform.

So we’re going to create a framework that will let us test various techniques more simply, like so:

`# | Bernoulli's limit assess -> x {(1 x⁻¹) ** (x)} # | Dörrie's bounds assess -> x { Sum × sum (1 x⁻¹) ** (x), (1 x⁻¹) ** (x 1) }`

Or, if we prefer, to specify a more appropriate range of trial values than just 1..∞, like so:

`| Dörrie's bounds`

`assess ->`

** x=(1, 10, 100 ... ⁶)**{`sum × sum (1 x⁻¹) ** (x),`

`(1 x⁻¹) ** ( x 1)`

`}`

Either way, the`assess`

function will calculate each result, determine when to give up on slow computations, tabulate the outcomes, color-code their accuracy, and print them out neatly labeled, like so:

`[1] Bernoulli's limit (x=1): (2)[0.001𝑠] (x=2): (2.)25[0.000𝑠] (x=4): (2.)441406[0.000𝑠] (x=8): (2.)565784514[0.000𝑠] (x=16): (2.)6379284973666[0.000𝑠] (x=32): (2.)676990129378183[0.000𝑠] (x=64): (2.)697344952565099[0.000𝑠] (x=128): (2.7)077390196880207[0.000𝑠] (x=256):`

`[4] Dörrie's bounds (x=1):(3) [0.001𝑠] (x=2): (2.) 8125[0.000𝑠] (x=4): (2.7)46582[0.000𝑠] (x=8): (2.7)2614604607[0.000𝑠] (x=16): (2.7)203637629093063[0.000𝑠] (x=32): (2.)8181001497167[0.000𝑠] (x=64): (2.)417960007014[0.001𝑠] (x=128):2. 718316125233677[0.001𝑠] (x=256):2. 7182904360195543[0.000𝑠] (x=512): (2.)3984544156[0.000𝑠] (x=1024):2. 7182823680062143[0.000𝑠] (x=2048): 101963411669[0.001𝑠] (x=4096): 2. 718281862205436[0.004𝑠] (x=8192):2. 7182818368966726[0.025𝑠] (x=16384):2. 718281830568581[0.109𝑠] (x=32768):2. 718281828986445[0.500𝑠] (x=65536):2. 7182818285908974[2.369𝑠] (x=131072):2. 7182818284920085[10.474𝑠]`

To implement all that, we start with a generic class component (*ie*another role)

suitable for storing, vetting, and formatting whatever the data we’re collecting:

`# Define a new type: Code that takes exactly one parameter ... subset Unary of Code where * .signature.params==1; # Reportable values, assessed against a target ... role Reportable [Cool :$target=""] { # Track reportable objects and eventually display them ... state Reportable @reports; END @reports ».display: @reports» .width.max; # Add reportable objects to tracking list, and validate ... submethod TWEAK (Unary: $ check={True}) { @ reports.push: self; $ check (self); } # Each report has a description and value ... has Str $ .desc handles width=>'chars'; has Cool $ .value handles *; # Display the report in two columns ... method display (Int $ width) { printf "% * s:% s n", $ width, $! desc, & .assess-value; } # Color-code the value for display ... method assess-value () { # Find leading characters that match the target ... my Int $ correct =($! value ~ ^ $ target) .match (/ ^ 0 /) .chars; # Split the value accordingly ... $! value.gist ~~ / ^ $`=(. ** {$ correct}) $=( S $=(. /; # Correct chars: blue; incorrect chars: red ... use Terminal :: ANSIColor; return colored ($. Str, 'blue') ~ colored ($. Str, 'red') ~ $ } }

We start by creating a new subtype ( (subset Unary) ) of the built-in`Code (type) (ie) the general type of blocks, lambdas, subroutines, (etc.) ) This new subtype requires that the`

(Code) ***************************************************************************************************** (object must take exactly one argument)`where * .signature.params==1`

).

Because (almost) everything in Perl 6 is an object, it's easy for the language to provide

these types of detailedintrospection methodson values, variables, types, and code.

(Next we create a pluggable component) (role Reportable) ) for building classes that generate self-organizing reports. This role isparameterizedto take a named value (`: $ target`

) that will subsequently be used to assess the accuracy of individual values being reported. That target value is specified to be of type(Cool), which allows it to be a string, a number, a boolean, a duration, a hash, a list, or any other type automatically convertible to a string or number. This type constraint will ensure that any value reported will later be able to be assessed correctly. The`: target`

parameter is optional; the default target being the empty string.

The`Reportable`

role is going to automatically track all reportable o bjects for us … and then generate the aggregrated report at the end of the program. So we declare a shared variable to hold each report (`state Reportable @reports`

), with a type specifier that requires each element of the array be able to perform the`Reportable`

role. To ensure that the reports are eventually printed, we add an`END`

(phaser) :

`END @reports ».display: @reports» .width.max;`

At the end of execution, this statement calls the`. display`

method of each report

(`@ reports ».display`

), passing it the maximum width of any report description

(`@ reports ».width.max`

) so that it can format the report into two clean columns.

To accumulate these reports, we arrange for each (Reportable) object to automatically add itself to the shared`@ reports`

array, when it is constructed … by declaring a`TWEAK`

submethod. Asubmethodis a class-specific, non-inherited method, suitable for specifying per-class initializers. The`TWEAK`

submethod is called automatically*after*an object is created: usually to adjust its initial value, or to test its integrity in some way.

Here, we’re doing both: by having the submethod add each object to the report list

(`@ reports.push: self`

) and by applying any`: check`

code passed to the constructor

(`$ check (self)`

). This allows the user to pass in an arbitrary test during the constructor call and have it applied to the object once that object is initialized. We’ll see shortly how useful that can be.

Each report consists of a string description and a value that can be any`Cool`

type, so we need per-object attributes to store them. We declare them with the`has`

keyword and a “Dot”*secondary sigil*to make them public:

`has Str $ .desc; has Cool $ .value;`

We also need to be able to access the string width of the description.

We could declare a method to provide that information:

`method width {$ .desc.chars}`

But, as this is just forwarding a request from the`Reportable`

object to the`$. desc`

object inside it, there’s a much easier way to achieve the same effect: we simply tell the`$. desc`

attribute that it should handle all object-level calls to`.Width`

by calling its own`.Chars`

method. Like so:

`has Str $ .desc`

**handles width=>'chars'**

More significantly, we also need to be able to forward methods to The`$. value`

attribute

(for example, to interrogate its`.Timing`

information). But as we don’t know what kind of object the value may be in each case (apart from generically being (Cool) ), we can’t know in advance which methods we may need to forward. So we simply tell`$. value`

to handle*whatever*the surrounding object itself can’t, like so:

`has Cool $ .value`

**handles ***;

Now we just need to implement the`. method that the`

`END`

*phaser*will use to output each`Reportable`

object. That method takes the width into which the description should be formatted, and prints it out justified to that width using a`printf`

. It also prints the value, which is pre-processed using the`. assess-value`

Method.

`. assess-value`

works out how well the value matches the target, by taking a

character-wise XOR between the two (`$! value ~ ^ $ target`

). For every character

(or digit in a stringified number) that matches, the XOR will produce a null character (`' 0'`

). For every character that differs, the resulting XOR character will be something else. So we can determine how many of the initial characters of the value match the target by counting how many leading`' 0'`

characters the XOR produces (`.match (/ ^ 0 /) .chars`

).

Then we just split the value string into three substrings using a regex , coloring the leading matches blue and the trailing mismatches red, using the`Terminal :: ANSIColor (Module.) `

```
```Once we have the role available, we can build a couple of`Reportable`

classes suited to our actual data. Each result we produce will need to be assessed against an accurate representation of***:

`class Result does Reportable [:target] {}`

And we'll also want to format our report with empty lines between the various techniques we're reporting, so we need a`Reportable`

class whose`.display`

method is overridden to print only empty lines:

`class Spacer does Reportable { method display (Int) {say ""} }`

Finally we build the`assess`

subroutine itself:

`constant TIMEOUT=3; # seconds; # Evaluate a block over a range of inputs, and report ... sub assess (Unary $ block ->Any) { # Introspect the block's single parameter ... my Parameter $ param=$ block.signature.params [0]; my Bool $ is-topic=$ param.name eq '$ _'; # Extract and normalize the range of test values ... my Any @values =do given try $ param.default. () { when! .defined && $ is-topic {Empty} when! .defined {1, * × 2 ... ∞} when.? infinite {.min, * × 2 ... ∞} default {.Seq} } # Introspect the test description (from doc comments) ... my Str $ label="[$block.line()] {$ block.WHY / / ''} ". trim; # New paragraph in the report ... Spacer.new; # Run all tests ... for @values Z $ label, "", * ->($ value, $ label) { Result.new: desc=>"$ label ($ param.name ()=$ value)", value=>timed {$ block ($ value)}, check=>{last if .timing>TIMEOUT} } if! @values { Result.new: desc=>$ label, value=>timed {$ block (Empty)} } }`

The subroutine takes a single argument: a (Code) object that itself takes a single parameter (which we enforce by giving the parameter the type (Unary) ).

We immediately introspect that one parameter (`$ block.signature .params [0]`

),

which is*(naturally) (a) Parameter object, and store it in a suitably typed variable*

(`my Parameter $ param`

). We also need to know whether the parameter is the

implicit topic variable (*aka*`$ _`

), so we test for that too.

Once we have the parameter, we need to determine whether the caller gave it a default value ... which will represent the set of values for which we are to assess the code in the block passed to`assess`

. In other words, if the user writes:

`assess ->`** N=1 .. 100**{some-function-of (N)}

... then we need to extract the default value ( (1 ..)

`) so we can iterate through those values and pass each in turn into the block.`

We can extract the parameter’s default value (if any!) By calling the appropriate introspection method:`$ param.default`

, which will return another (Code) object that produces the default value when called. Hence, to get the actual default value we need to call`.default`

, then call the code`.default`

returns. That is:`$ param.default. ()`

Of course, the parameter may not have a default value, in which case`.default`

will return an undefined value. Attempting the second call on that undefined value would be fatal, so we make the attempt inside a`try`

, which converts the exception into yet another undefined value.

We then test the extracted default value to determine what it means:

`when! .defined && $ is-topic {Empty} when! .defined {1, * × 2 ... ∞} when.? infinite {.min, * × 2 ... ∞} default {.Seq}`

If it’s undefined, then no default was specified, so we either use an empty list as our test values (if the parameter is just the implicit topic, in which case it’s a parameterless one-off trial), or else we use the endlessly doubling sequence`1, 2, 4 ... ∞`

. Using this sequence instead of`1..∞`

gives us reasonable coverage at every numeric order of magnitude, without the tedium of trying every single possible value.

(If the default was a range to infinity (`when. ? infinite`

), then we adjust it to similar sequence of doubling values to infinity, starting at the same lower bound (`.min`

). And if the value is anything else, we just use it as-is, only converting it to a sequence (`.Seq`

).

Once we have the test values, we need a description for the overall test. We could have simply added a second parameter to`assess`

, but the powerful introspective capabilities of Perl 6 offer a more interesting alternative …

We need to convey three pieces of information: the line number at which the call to`assess`

was made, a description of the trial being assessed, and the trial value for each trial. However, to avoid uncomely redundancy, only the first trial needs to be labeled with the line number and description; subsequent trials need only show the next trial value.

We can get the line number by introspecting the code block: ($ block.line ())

But where can we get the description from?

Well … why not just read it directly from the comments ?!

(In Perl 6, any comment that starts with a vertical bar)*ie*`# | Your comment here`

) is a special form of documentation known as a*declarator block*. When you specify such a comment, its contents are automatically attached to the first declaration following the comment. That might be a variable declared with a`My`

, a subroutine declared with a`sub`

or (Multi) , or (in this case) an anonymous block of code declared between two braces.

In other words, when we write:

`# | Bernoulli's limit assess -> x {(1 x⁻¹) ** (x)}`

… the string`"Bernoulli's limit"`

is automatically attached to the block that is passed into`assess`

. We could also put the documentation comment*After*the block, by using`#=`

as the comment introducer, instead of`# |`

:

`assess -> x {(1 x⁻¹) ** x} #=Bernoulli's limit`

Either way, Perl 6’s advanced introspective facilities mean that we can retrieve that

documentation during program execution, simply by calling the block’s`WHY (method)`

*(because comments are supposed to tell you “WHY”, not “HOW”)*.

So we can generate our description by asking the block for its line number and its documentation, making do with an empty string if no documentation comment was supplied (`"[`

).**$block.line()**] {**$ block.WHY**// ''} "

Now we’re ready to run our tests and generate the report . We start by inserting an empty line into the report … by declaring a`Spacer object. Then we iterate through the list of values, and their associated labels, interleaving the two with a “zip” operator ( (Z) )). The labels are the initial label we built earlier, then an empty string, then a “whatever” (`

`*`

), which tells the zip operator to reuse the preceding empty string as many times as necessary to match the remaining elements of`@ values `

. That way, we get the full label on the first line of the trial, but no repeats of it thereafter.

The zip produces a series of two-element arrays: one value , one label. We then iterate through these, building an appropriate`Result`

object for each test:

`Result.new: desc=>"$ label ($ param.name ()=$ value)", value=>timed {$ block ($ value)}, check=>{last if .timing>TIMEOUT}`

The description for the report is the label, followed by the block’s parameter name (`$ param.name ()`

) and the current trial value being passed to it on this iteration (`$ value`

). The value for the report is just the timed result of calling the block with the current trial value passed to it (`timed {$ block ($ value)}`

).

But we also want to stop testing when the tests get too slow , so we pass the`Result`

constructor A`check`

argument as well, which causes its`TWEAK`

submethod to execute the check block once the result has been added to the report list. Then we arrange for the`check`

block to terminate The surrounding`for`

loop (*ie*`last`

) if the timing of the new object exceeds our chosen timeout. The call to`.Timing`

will be invoked on the (Result) object, which (not having a`timing`

method itself) will delegate the call to its`$. value`

attribute, which we specified to handle “whatever” methods the object itself can’t deal with.

The only thing left to do is to cover the edge-case where the user provides no test values

at all (*ie*when there are no`@ values [46.717𝑠] to iterate through). That can happen either when an explicit empty list of default values is passed to`

`Assert`

, or when the block passed in doesn’t explicitly declare a parameter at all (and therefore defaults to the implicit topic parameter:`$ _`

). In either case, we need to call the block exactly once, without any argument. So if the array of test values has no elements (`if @ values.elems==0`

),

we instantiate a single`Result`

object, passing it the full label, and the timed result of calling the block with a*(literally)*empty argument list:

`if! @values { Result.new: desc=>$ label, value=>timed {$ block (Empty)} }`

And we’re done. We now have an introspective and compact way of performing multiple trials on a block, across a range of suitable values, either explicit or inferred, with automatic timing of — and timeouts on — each trial.

So let’s get back to computing the value of𝑒…

#### 𝑒 (is for) eversion

The constant (𝑒) is associated with Jacob Bernoulli in another, entirely unrelated way. In his posthumous 1712 publication,*Ars Conjectandi*, Bernoulli explored the mathematics of binomial trials: random experiments in which the results are strictly binary:*success*or*failure*, (true) or (false) , (yes) or*No*,*heads*or*tails*.

One of the results of binomial theory has to do with the probability of extremely bad luck.

If we conduct a random binomial trial where the probability of success is (1) ∕_{(k)}, then the probability of failure must be 1 – (1) ∕_{(k)}. Which means that, if we repeat our same random trial

(k) times, then the probability of failing every time is (1 – (1) ∕_{(k)})^{(k)}. As*K*grows larger, this probability increases from zero (for (k)=1), to 0. 25 (for (k)=2), to 0. 296296296296 … (for*K*=3), to 0. 31640625 (for (K)=4), gradually converging on an asymptotic value of 0. 36787944117144233 … (for*K*=∞). And the value 0. 36787944117144233 … is exactly (1) ∕_{𝑒}.

Which means that (1 – 1) ***_{(k)})^{– (K)}must tend towards𝑒as (K) tends to ∞. So we can try:

`# | Bernoulli trials assess -> k=2..∞ {(1 - k⁻¹) ** -k}`

… which tells us:

`[20] Bernoulli trials (k=2) ):(4) [0.000𝑠] (k=4):`

Which, sadly, converges no faster than Bernoulli’s original loan sharking scheme .

#### 𝑒 (is for) exclamation

Despite its disappointing performance, the Bernoulli trials approach highlights a useful idea. The constant𝑒appears in a great many other mathematical equations, all of which we could rearrange to produce a formula starting:𝑒=…

For example, in 1733 Abraham de Moivre firstpublishedan asymptotic approximation for the factorial function, which*(just a few days later! )*wasrefinedby James Stirling, after whom the approximation is now named. That approximation is:*n!*`≅``√2π [46.717𝑠] **************************************************************** (n)× (`^{(n) (∕)𝑒)nwith the approximation becoming more accurate as (n) becomes larger.}

Rearranging that equation, we get:𝑒`(≅)`(n) /_{(n) ********************************************************************************************** (√)n!}

For which we’re going to need both an (n) – th root operator and a factorial operator. Both of which are missing from standard Perl 6. Both of which are trivially easy to add to it:

`# n-th root of x ... sub infix:(Int $ n, Int $ x ->Numeric (is tighter) & [**] ) { $ x ** $ n⁻¹ } # Factorial of x ... sub postfix:(Int $ x ->Int) { [×] 1 .. $ x }`

The new infix`√`

operator is specified to have a precedence just higher than the existing`** (exponentiation operator)`

`is tighter (& [**])`

)). It simply raises the value after the`√`

to the reciprocal of the value before the`√`

.

The new postfix`!`

operator multiplies together all the numbers less than or equal to its single argument (`1 .. $ x`

), using areductionby multiplication (`[×]`

).

With those two new operators available, we can now write:

`# | de Moivre / Stirling approximation assess -> n {n / n√n! }`

Unfortunately, the results are less than satisfactory:

`[30] de Moivre / Stirling approximation (n=1):(1) [0.000𝑠] (n=2):`

This approach converges on (𝑒)*even slower*than the previous ones, and for the first time

Perl 6 has actually failed us when it comes to a numerical calculation. Those zeroes are indicating that the compiler has been unable to take the 256 th root of the factorial of 256.

Or deeper roots of higher numbers.

It computed the factorial itself (*ie*8578177753428426541190822716812326251577815202 79485619859655650377269452553147589377440291360451408450375885342336584306 15719683469369647532228928849742602567963733256336878644267520762679456018 79688679715211433077020775266464514647091873261008328763257028189807736717 81454170250523018608495319068138257481070252817559459476987034665712738139 28620523475680821886070120361108315209350194743710910172696826286160626366 24350228409441914084246159360000000000000000000000000000000000000000000000 000 000 000 000 000 00) without difficulty, but then taking the 256 th root of that huge number (by raising it to the power of (1) ********************************************************************************************** (∕) 256) failed. It incorrectly produced the value ∞, whereupon*n*divided by that wrong result produced the zero. The point of failure seems to be around 170! or 10^{308}, which looks suspiciously like an internal 64 – bit floating-point representation limit.

Of course, we could work around that limitation, by changing the way we compute*n*– th roots. For example, the*n*– th root of a number also given by: 10^{log10(X)∕n}

So we could try:

(# n-th root of x …)`sub infix:(Int $ n, Int $ x ->Numeric) is tighter (& [**]) {`

**10 ** (log 10 ($ x) / $ n)**`}`

… but we get exactly the same problem: the built -in`log 10`

function breaks at around 10^{308}, meaning we can’t apply it to factorials of numbers greater than 170.

But when (X) is an integer, there’s a surprisingly good approximation to log_{10}(X) that doesn’t have this 10^{308}limitation at all: we simply count the number of digits in*X*and subtract ***.

In the worst cases, this result is out by no more than ± 0.5, but that means its*average*error over a sufficiently large range of values … is zero.

Using that approximation for (n) – th roots:

(# n-th root of x …)`sub infix:(Int $ n, Int $ x ->Numeric) is tighter (& [**]) {`

`10 ** (`

**($ x.chars - ½)**/ $ n)`}`

… we can now extend our assessment of the de Moivre / Stirling approximation far beyond*n*=170. In which case we find:

`[30] de Moivre / Stirling approximation (n=1): 0. 31622776601683794[0.000𝑠] (n=2):1. 1246826503806981[0.000𝑠] (n=4):1. 6867860137143293[0.000𝑠] (n=8): (2.)190735707411489[0.000𝑠] (n=16): (2.)2928201123791405[0.000𝑠] (n=32): (2.)4875680967640825[0.000𝑠] (n=64): (2.)5570691577279274[0.001𝑠] (n=128):2.6522607579574027[0.001𝑠] (n=256):2.6898269484112647[0.005𝑠] (n=512): (2.)69742667825642[0.006𝑠] (n=1024): (2.7)080909004243128[0.012𝑠] (n=2048): (*******************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************************)1166091674111[0.040𝑠] (n=4096): 2. 7150077947508775[0.159𝑠] (n=8192):2. 716181527473568[0.678𝑠] (n=16384):2. 7171648275814224[3.049𝑠]`

To our disgust, the convergence of this approach clearly does not accelerate at higher values of*n*.

In fact, even when (n) is over a million, the result is still only accurate to three decimal places; worse even than the classicpalindromic fractional approximation:

`# | Palindromic fraction assess {878 / 323 }`

… which gives us:

`[40] Palindromic fraction: 2. 7182 66[0.001𝑠]`

Alas, the search continues.

#### 𝑒 (is for) estimation

Let’s switch back to probability theory. Imagine a series of uniformly distributed random numbers in the range 0..1. For example:

`0. 162532, 0. 682623, 0. 4052625, 0. 42167261, 0. 99765261, ...`

If we start adding those numbers up, how many terms of the series do we need to add

together before the total is greater than 1? In the above example, we’d need to add

the first three values to exceed 1. But in other random sequences we’d need to add only

two terms (*eg*(0.) , 0. 55326178, …) and sometimes we’d need to add quit e a few more (*eg*`0. 1282827, 0. 00262671, 0. 39838722, 0. 386272617, 0. 77282873, ...`

). Over a large number of trials, however, the average number of random values required for the sum to exceed 1 is*(you guessed it)*:𝑒.

So, if we had a source of uniform random values in the range 0..1, we could get an approximate value for***by repeatedly adding sufficient random values to exceed 1,

and then averaging the** number**of values we required each time, over multiple trials.

Which looks like this in Perl 6:

`# | Stochastic approximation assess -> trials=(10 ², 10 ³, 10 ⁴, 10 ⁵, 10 ⁶) { sum ((1..trials) .map: {([ ] rand xx ∞) .first (*>1): k 1} ) / trials }`

(That is: we conduct a specified number of trials (`1..trials`

), and for each trial (`.Map:`

)

we generate an infinite number of uniform random values (`rand xx ***`

), which we then convert to a list of progressive partial sums (`[ ]`

). We then look for the first of these partial sums that exceeds 1 (`.first (*>1)`

), find out its index in the list (`: K`

) and add 1

(because*indices*start from zero, but*counts*start from 1

The result is a list of counts of how many random values were required to exceed one in each of our trials. As𝑒is the*average*of those counts, we (sum) them and divide by the number of trials. And find:

`[50] Stochastic approximation (trials=100): (2.) 62[0.020𝑠] (trials=1000) : 2.7[0.045𝑠] (trials=10000): (2.)79[0.357𝑠] (trials=100000): (2.7)256[3.651𝑠] (trials=1000000) :2. 718698[43.185𝑠]`

That’s pretty good … for random guessing. If we’d kept it running for a greater number of trials, we’d eventually have gotten reasonable accuracy. But it’s unreliable: sometimes** losing**accuracy as the number of trials increases. And it’s slow: only three digits of accuracy after a million trials … and 40 seconds of computation. To get a useful number of correct digits we’d need billions, possibly trillions, of trials … which would require tens, or thousands, of hours of computation.

So on we go ….

#### 𝑒 (is for) efficiency

Or, rather, (back) we go. Back to 1669, to that Isaac Newton of mathematical geniuses:

Isaac Newton. In a manuscript entitled*De analysi per aequationes numero terminorum infinitas*Newton set out a general approach to solving equations that are infinite series,

an approach that implies a highly efficient way of determining𝑒.

Specifically, that:`𝑒``=``Σ(1) ********************************************************************************************** ∕`_{(K!)}`for (k) from 0 to ∞`

So let’s try that:

`# | Newton's series assess -> k=0..∞ {sum (0..k) »!» ⁻¹}`

Here we compute𝑒by taking increasingly longer subsets of length (k) from the infinite series of terms (` k=0..∞`

). We take the indices of the chosen terms (`(0..k)`

), and for each

of them (`»`

) take its factorial (`!`

). Then for each factorial (`»`

) we take its reciprocal (`⁻¹`

).

The result is a list of the successive terms (1) ∕_{K!}, which we finally add together ( (sum) ) to get𝑒:

`[60] Newton's series (k=0):(1) ************************************************************************************************************ [0.001𝑠] (k=1): (2)[0.000𝑠] (k=2): (2.) (5) [0.000𝑠] (k=3): (2.)666667[0.000𝑠] (k=4): (2.7)08333[0.001𝑠] (k=5): (2.)6667[0.001𝑠] (k=6): (2.)056[0.002𝑠] (k=7): (2.)54[0.001𝑠] (k=8): (2.)79[0.005𝑠] (k=9): (2.) (2) [0.001𝑠] (k=10): (2.)01[0.001𝑠] (k=11): (2.) (6) [0.001𝑠] (k=12): (2.)3) [0.002𝑠] (k=13):2. 718281828447[0.002𝑠] (k=14): (2.)82[0.002𝑠] (k=15):2. 71828182845899 [0.002𝑠] (k=16): (2.)23[0.002𝑠] (k=17):2. 718281828459045[0.002𝑠] (k=18): (2.)27[0.002𝑠] (k=19): 7182818284590452[0.003𝑠] (k=20) :2. 71828182845904523534[0.007𝑠] ⋮`

Finally … some real progress. After summing only 20 terms of the infinite (1) ∕_{K!}series, we have 19 correct decimal places, and*(at last!)*a reasonably accurate value of***.

And we can do even better:𝑒can be decomposed into many other infinite summations.

For example: in 2003 Harlan Brothersdiscoveredthat𝑒`=``Σ`^{( 2k 1)}∕_{(2) ********************************************************************************** (k) )!}

which we could assess with:

`# | Brothers series assess -> k=0..∞ { sum (2 «×« (0..k) » » 1) »/« (2 «×« (0..k)) »! }`

By making every arithmetic operator aHyperoperator, we can compute the entire series of 0 ..*k*terms in a single vector expression and then sum them to get***.

The code for the Brothers formula might be a little uglier than for Newton’s original,

but it makes up for that by converging twice as fast, giving us 19 correct decimal places from just the first ten terms in the series:

`[70] Brothers series (k=0): 1[0.003𝑠] (k=1): (2.) (5) [0.000𝑠] (k=2): (2.7)08333[0.001𝑠] (k=3): (2.)056[0.001𝑠] (k=4): (2.)79[0.001𝑠] (k=5): (2.)01[0.001𝑠] (k=6): (2.) (3) [0.001𝑠] (k=7): (2.)82[0.001𝑠] (k=8): (2.)23[0.001𝑠] (k=9): (2.)27[0.001𝑠] (k=10): (2.) (4) [0.001𝑠] ⋮`

#### 𝑒 (is for) EPSILON

We’re making solid progress on an accurate computation of𝑒with these two Newtonian series, but that ugly (and possibly scary) hyperoperated assessment code is still kinda irritating. And too easy to get wrong.

Given that these efficient methods all work the same way — by summing (an initial subset of) an infinite series of terms — maybe it would be better if we had a function to do that for us. And it would certainly be better if the function could work out by itself exactly how much of that initial subset of the series it actually needs to include in order to produce an accurate answer … rather than requiring us to manually comb through the results of multiple trials to discover that.

And, as so often in Perl 6, it’s surprisingly easy to build just what we need:

`sub Σ (Unary $ block ->Numeric) { (0..∞) .map ($ block) .produce (& [ ]). & converge }`

We call the subroutine`Σ`

, because that’s the usual mathematical notation for this function*(okay, yes, and just because we can)*. We specify that it takes a one-argument block, and returns a numeric value (

`Unary $ block ->Numeric`

), with the return value representing a “Sufficiently accurate” summation of the series specified by the block.To accomplish that, it first builds the infinite list of term indexes (`0..∞`

) and passes each in turn to the block (`.map ($ block)`

). It then builds successive partial sums of the resulting terms (`.Produce (& [ ])`

). That is, if the block was`{1 / k! }`

, then the list created by the`.map`

would be:`(1, 1, (1) ∕`

and the_{2) , (1) ∕ (6) , (1) ********************************************************************************************** (∕) 24}, (1) ∕_{120}, ...)`.produce (& [ ])`

method call wouldprogressively addthese, producing the list: (1 1, 1 1 ) ********************************************************************************************* 1) ∕ (2) , 1 1 1) *** (2) (1) ∕ (6) , 1 1 (1) ********************************************************************************************** (∕) *********************************************************************************************** (2) (1) *** (6) 1) ***_{24}, 1 1 (1) ∕ (2) (1) ∕_{6} (1) ∕_{24} (1) ∕_{120}, …)

That is:`(1, 2, 2.5, 2.) , 2. 708, 2. 717, ...)`

.

We set the calculation up this way because we need to be able to work out when to stop adding terms, which will be when the successive elements of the`.produce (list) converge`

to a consistent value. In other words, when two successive values differ by only an Inconsequential amount.

And, conveniently, Perl 6 has an operator that can tell us precisely that:

The`***`

*is-approximately-equal-to*operator(or its ASCII equivalent:`=~=`

).

So we could write a subroutine that takes a list and returns the first “converged” value

from it, like so:

`sub converge (Iterable $ list ->Numeric) { $ list.rotor (2=>- 1) .first ({.head ≅ .tail}). tail }`

The`.ROTOR`

methodextracts sublists of*N*elements from its list. Here we tell it to extract two elements at a time, but to also make them overlap, by stepping back one place (`- 1`

) between each extraction. The result is that, from a list such as`(1, 2, 2.5, 2. 666, 2. 708, 2. 717…)`

, we get a list of lists of every pair of adjacent values:`((1, 2), (2, 2.5) , (2.5, 2.) 667), (2.) 667, 2. 708), (2.) 708, 2. 717)…)`

Then we simply step through the list of lists, looking for the first sublist in which the head and tail elements are approximately equal (`.first ({.head ≅ .tail})`

). That gives us back a single sublist, from which we extract only the more-accurate tail element (`.TAIL`

).

We can then just apply this function to the list of partial sums Being produced in`***`

:

`(0..∞) .map ($ block (.produce) & [ ])`

**. & converge**

… which is just a conveniently left-to-right way of passing the entire list into`converge`

.

Of course, we could also have written it as a normal (name-arglist) style subroutine call:

**Converge**(0..∞) .map ($ block (.produce) & [ ])

… if that makes us more comfortable.

The insanely cool thing about all this — and the only reason it works at all — is that every component of the two method-call chains within`Σ`

and`CONVERGE`

is** lazily evaluated**.

Which means that

`.map`

doesn’t actually execute the block on any of the`(0..∞)`

values, and`.Produce`

doesn’t progressively add any of them together, and`.Rotor`

doesn’t extract any overlapping pairs of them, and`.first`

doesn’t search any of them … unless the final result requires them to. The`.Map`

only invokes the block as many times as necessary to get enough values for`.Produce`

to add, to get enough values for`.Rotor`

to extract, to get enough values for`.first`

to find the first approximately equal pair.I truly love that about Perl 6: not only does it allow you to write code that’s concise, expressive, and elegant; your concise, expressive, elegant code is naturally efficient as well.

Meanwhile, we now have a much better (*ie*more concise, more expressive, more elegant) way of generating a highly accurate value of𝑒:

`# | Newton's series assess {Σ -> k {1 / k! }} # | Brothers series assess {Σ -> k {(2 × k 1) / (2 × k)! }}`

… which give us the straightforward answers we were looking for :

`[80] Newton's series: 2. 7182818284590452 27[0.007𝑠]`

`[83] Brothers series: (2.) (4) [0.002𝑠]`

#### 𝑒 (is for) epigram

And that would be the end of the story … except that we’ve still ignored half of the possibilities. Every technique we’ve tried so far has been mathematical in nature.

But Perl 6 is not just for algebraists or statisticians or probability theorists.

It’s also for linguists and authors and poets and all other lovers of natural language.

So how could we use natural language to compute an accurate value of𝑒?

Well, it turns out that algebraists and statisticians and probability theorists have been doing that for centuries. Because once you’ve spent several hours (or days, or weeks) manually calculating the first eight digits of***, you** never want to have to do that again!**So you come up with a mnemonic: a sentence that helps you remember those hard-won digits.

Most mnemonics of this kind work by encoding each digit in the length of successive words.

For example, to remember the constant`1. 23456789`

, you might encode it as:*“I am the only local Aussie abacist publicly available ”*. Then you just count the letters

of each word to extract the digits.

As usual, that’s trivial to implement in Perl 6:

`sub mnemonic (Str $ text ->Str) { with $ text.words ».trans (/` /=>'') ». Chars { return "{.head}. {. tail - 1) .join}" } }

We first extract each word from the text (`$ text .words`

), and for each of them (`»`

)

we remove any punctuation characters by translating them to empty strings

(`.trans (/`

), and finally count the number of remaining

characters in each word (`». Chars`

)). We then take the first element from that list of

word lengths`head`

), add a dot, and then append the concatenation of the rest

of the*N*– 1 character counts (`. Tail - 1) .Join`

), and return that as the

string representation of the resulting number.

Then we test it:

`# | Mnemonic test assess { mnemonic "I am the only local Aussie abacist publicly available " }`

which prints:

`[90] Mnemonic test: 1 . 23456789[0.002𝑠]`

… which is clearly a very poor approximation to𝑒.

(But for three centuries people have been making up better ones.) One of the most widely used is the slightly self-deprecating:

`# | Modern mnemonic assess { mnemonic "It enables a numskull to remember a sequence of numerals " }`

… which gives us nine correct decimal places:

`[100] Modern mnemonic: (2) 718281828[0.003𝑠]`

If we need more accuracy, we can just compose a longer sentence . For example:

`# | Titular mnemonic assess { mnemonic "To compute a constant of calculus: (A treatise on multiple ways) " }`

… which produces one additional digit:

`[110] Titular mnemonic: 2. 7182818284[0.002𝑠]`

Or, for better accuracy than**(any)**of the mathematical approaches so far, we could use Zeev Barel’s (self-referential description) :

`# | Extended mnemonic assess { mnemonic "We present a mnemonic to memorize a constant so exciting that Euler exclaimed: '!' when first it was found. Yes, loudly: '!'. My students perhaps will compute e, via power or Taylor series, an easy summation formula. Obvious, clear, elegant! " }`

… which gives us far more accuracy than we’d ever actually need:

`[120] Extended mnemonic: 2. 718281828459045235360287471352662497757[0.010s]`

#### 𝑒 (is for) eclectic

And even that isn’t the end of the story. Just like π (its main rival for*World’s Most Awesome Mathematical Constant*), (𝑒) exerts a strange fascination over the mathematically whimsical.

For example, in 1988, Dario Castellanos (published) the following identity:𝑒`=``(π (4) π (5) )`^{(1) ∕ (6)}

Which, translated to Perl 6 is:

`# | Castellano's coincidence assess {(π⁴ π⁵) ** ⅙}`

… and gives us seven decimal places of accuracy:

`[130] Castellano's coincidence: 2. 7182818 08611915[0.001𝑠]`

And those of us who can remember the digits 1 to 9*(or who know an Aussie abacist)*

can use Richard Sabey’s formula:`(𝑒)``=``(1 2`^{– 3 x (4 5)})^{.6 × .7 8 (9)}:

`# | Sabey's digits assess {(1 2 ** (- 3 × (4 5))) ** (. 6 × .7 8⁹)}`

… which (fittingly) gives us nine correct digits in total:

`[140] Sabey's digits: 2. 71828182 6838823[0.000𝑠]`

But those curiosities are as*nothing*compared to the true highlands of***Exploration.

For example, Maksymilian Piskorowski found that if you happen to have a spare eight 9s, you can compute`(𝑒)``=``(`^{9}∕ (9) 9^{– 9 (9)}) (9) ********************************************************************************************* 9 (9) , which is accurate to a little over 369*million*

We could translate that easily enough to Perl 6:

`# | Piskorowski's eight 9s assess {(9/9 9 ** - 9 ** 9) ** 9 ** 9 ** 9}`

But, alas, our assessment fails*(eventually)*, producing a disappointing:

`[150] Piskorowski's eight 9s: 1) [332242.506𝑠]`

… because the value of 9^{– 9 (9)}is so vanishingly small that adding it to (9) ∕ (9) in Perl 6

merely produces 1, and then 1 (9) ********************************************************************************************* (9) ********************************************************************************************* (9) is still 1.

Piskorowski’s incalculable ⅓ billion decimal places of accuracy seemed like the (il ) logical end-point of this quest. But only until the aforesaid Richard Sabey spoiled the game for everyone, by reformulating his aforementioned pan-digital formulation to:𝑒`=``( 1 9`^{– 4 (7 × 6)})^{(3) ********************************************************************************************* (2) 85}

Which is accurate to a staggering 18457734525360901453873570 decimal places

(that’s (4)*octillion*digits) … but which, tragically, immediately underflows Perl 6’s numeric representation when attempting to compute the initial 9^{– 442}; Perl 6 being unable to accurately represent (1) ∕ (9) 19342813113834066795298816.

Meanwhile, if you’d like to further explore these and other𝑒– related exotica,

check out Erich Friedman’s mesmerizing*Math Magic (website) .*

#### 𝑒 (is for) exquisite

There is still one higher mathematical summit for us to surmount in our quest for𝑒.

The pinnacle of mathematical elegance, the peak of arithmetical pulchritude,

the single most beautiful equation in all of mathematics:Euler’s Identity

In 1748 Leonhard Euler published his masterwork:*Introductio in analysin infinitorum*,

in which he included the first mention of the general (Euler Formula) ***************************************************************************************:`𝑒`^{(ix)}`=``cos`*x**i*sin (x) .

Although not explicitly mentioned in the treatise, this formula implies a remarkable special case (at*x*=π) of:`(𝑒)`^{Iπ}`=``– 1 0 (i)`

This special-case equality is nowadays more usually written:`𝑒`^{iπ} 1=0

Thereby uniting the five most important constants in mathematics.

Quite apart from this extraordinarily lovely unification of mathematical fundamentals,

for our purposes the significant point here is that one of the five components is (𝑒) .

And, if we rearrange the formula to isolate that constant, we get: (𝑒)`=``(- 1)`^{(1) ***πi}

which we can easily assess in Perl 6:

`# | From Euler's Identity assess {(-1) ** (π × i) ⁻¹}`

Unfortunately, Perl 6 is not (yet) smart enough to infer from the imaginary exponent that it needs to use the`Complex`

version ofThe`**`

operator*(well, yes, of course complex mathematics is already built into Perl 6)*. So we get back:

`[160] From Euler's Identity:(NaN) [0.000𝑠]`

… because the non-complex exponentiation fails when given a complex exponent,

producing the value (NaN NaN i) .

(But if we start with a suitably 2D version of -1)*ie*-1 0*i*), like so:

`# | From Euler's Identity assess {(-1 0i) ** (π × i) ⁻¹}`

… we get the correct complex arithmetic, and a highly accurate answer from it:

`[160] From Euler's Identity: 2. 718281828459045[0.000𝑠]`

#### 𝑒 (is for) Effortless

It’s fitting that we have now come full circle: finding Euler’s Number

from the special case of Euler’s Formula that is Euler’s Identity.

Euler’s Ouroboros, if you will.

All that effort … to end up more or less back where we started. Which is highly ap propriate,

because where we started already had the answer built in. First of all, in the form of

the standard`exp`

function, which returns the value of (𝑒)^{x}.

So we could have tried:

`# | Built-in exp () function assess -> x=1 {exp (x)}`

… which would have given us:

`[170] Built-in exp () function (x=1): 2. 718281828459045[0.000𝑠]`

But even that is considerably more effort that we actually need in Perl 6.

Because*(of course)*the constant itself is also built right in to the language:

`# | Built-in e constant assess {e}`

… and produces an equally accurate result:

`[180] Built-in e constant: 32768[0.000𝑠]`

So the optimal solution to the original task was just five characters long :

`say e`

… which shall henceforth be known as:*“Euler’s One-liner”*.

Damian

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